CCL: symmetry breaking



 Sent to CCL by: Susi Lehtola [susi.lehtola(a)alumni.helsinki.fi]
 On 06/09/2017 05:59 AM, Ulrike Salzner salzner*_*fen.bilkent.edu.tr wrote:
 
 Hello,
 
I am comparing three large conjugated pi-systems with density functional theory (global and range-separated hybrids). The difference between them is that one contains phenyl rings, one thiophene, and the last one selenophene.
 
All three of molecules have UDFT instability with B3P86 with 30% HF exchange.
 
With open-shell singlet calculations and 50:50 HOMO-LUMO mixing, the phenyl and seleophene systems converge to open-shell biradical ground states that lie 0.02 and 0.12 eV below the closed-shell states. The thiophene system does not break the symmetry. This is odd because selenophene and thiophene system behave usually very similar.
 
In addition, excited calculations with UTDDFT give negative triplet excitation energies for all of them when the closed-shell wave are used.
 
As triplet excitation energies are probably underestimated with UTDDFT, I checked the ground state triplet energies. The triplets lie 1.24 eV (phen), 0.79 eV (thio), and 0.61 eV (seleno) above the closed-shell singlets. Again there is no reason why the thiophene system should differ from the other two.
 
Is there any way other way to find the broken the symmetry ground state? Or - is the lack of a broken symmetry solution after 50:50 HOMO-LUMO mixing sufficient to prove that the ground state is closed-shell?
 
HOMO-LUMO mixing stability is a necessary but not sufficient condition for wave function stability. You should run full stability analysis on the closed-shell singlet state to find out if the solution you've found really is a local minimum.
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 Mr. Susi Lehtola, PhD             Chemist Postdoctoral Fellow
 susi.lehtola(a)alumni.helsinki.fi   Lawrence Berkeley National Laboratory
 http://www.helsinki.fi/~jzlehtol  USA
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