From chemistry-request@server.ccl.net Mon Sep 11 12:59:52 2000 Received: from junco.tcc ([193.137.208.70]) by server.ccl.net (8.8.7/8.8.7) with ESMTP id MAA31349 for ; Mon, 11 Sep 2000 12:59:50 -0400 Received: from qta.qui.uc.pt (IDENT:paulo@localhost.localdomain [127.0.0.1]) by junco.tcc (8.9.3/8.9.3) with ESMTP id RAA13596; Mon, 11 Sep 2000 17:58:14 +0100 Sender: paulo@junco.tcc Message-ID: <39BD0F25.AA9F5F67@qta.qui.uc.pt> Date: Mon, 11 Sep 2000 17:58:13 +0100 From: "Paulo E. Abreu" X-Mailer: Mozilla 4.75 [en] (X11; U; Linux 2.2.17 i686) X-Accept-Language: en MIME-Version: 1.0 To: "Isaac B. Bersuker" CC: chemistry@ccl.net Subject: Re: CCL:HYBRIDIZATION NOT "REAL";V. FOCK References: <39BC0884.4ADBB8E@trentu.ca> <39BD05DE.2A4DFC2C@eeyore.cm.utexas.edu> <39BCF8F6.F79F85FD@qta.qui.uc.pt> <39BD2513.9E11C49E@eeyore.cm.utexas.edu> Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit "Isaac B. Bersuker" wrote: > Yes, you can: hybridization changes the charge distribution which is, in principle > observable Sorry to disagree (again) with you but I dont think that is a correct answer. Bonding changes the charge distribution not hybridization. Besides what do you mean by changing the charge distribution ? Comparing it with to the free atoms ? Orbital are models, and within these models we can describe chemical bonding with various approaches (MO or VB). Hybridization is only used in VB theory, because in MO the symmetry of the molecule plays an important role in determining the coefficients of the orbitals. Remember that to use hybrid-orbitals you must a priori know the geometry of the molecule. Paulo E. Abreu -- Departamento de Quimica e-mail:qtabreu@ci.uc.pt Universidade de Coimbra TEL:351 239 852080 3049 Coimbra Codex FAX:351 239 827703 Portugal