From owner-chemistry@ccl.net Fri Apr 8 08:29:00 2011 From: "Marcel Swart marcel.swart~!~icrea.cat" To: CCL Subject: CCL: preparation energy of EDA Message-Id: <-44319-110408082105-17293-p4e7ts1SMOJ0mQ/IclkCJw ~~ server.ccl.net> X-Original-From: Marcel Swart Content-Type: multipart/alternative; boundary=Apple-Mail-2--311976908 Date: Fri, 8 Apr 2011 14:20:53 +0200 Mime-Version: 1.0 (Apple Message framework v1084) Sent to CCL by: Marcel Swart [marcel.swart(_)icrea.cat] --Apple-Mail-2--311976908 Content-Transfer-Encoding: quoted-printable Content-Type: text/plain; charset=iso-8859-1 Much depends on the electronic state of your system and the fragments; for instance, for a hydrogen-bond the preparation energy contains only deformation energy: M. Swart, C. Fonseca Guerra and F.M. Bickelhaupt=20 "Hydrogen Bonds of RNA Are Stronger than Those of DNA, But NMR Monitors = Only Presence of Methyl Substituent in Uracil/Thymine" J. Am. Chem. Soc. 2004, 126, 16718-16719 http://dx.doi.org/10.1021/ja045276b For systems containing transition-metals, it also contains other terms (valence excitation, ligand-ligand): M. Swart "Accurate spin-state energies for iron complexes" J. Chem. Theory Comput. 2008, 4, 2057-2066 http://dx.doi.org/10.1021/ct800277a And for other fragments, you may need to include pairing as well: F. M. Bickelhaupt, E. J. Baerends=20 The Case for Steric Repulsion Causing the Staggered Conformation of = Ethane=20 Angew. Chem. 2003, 115, 4315-4320 http://www3.interscience.wiley.com/cgi-bin/abstract/105557159/ABSTRACT All that is explained in detail in: F. M. Bickelhaupt, E. J. Baerends Kohn-Sham Density Functional Theory: Predicting and Understanding = Chemistry In: Rev. Comput. Chem.; K. B. Lipkowitz and D. B. Boyd, Eds.; Wiley-VCH: = New York, 2000, Vol. 15, pp. 1-86 and in the above mentioned papers. For any specific ADF questions (technical ones), it is better to have a = look at ADF forums and ask the question there: http://www.scm.com/forums/ Marcel On Apr 8, 2011, at 12:55 PM, Ajitha. John aji.john07|a|gmail.com wrote: > Dear abdelghani, >=20 > EDA analysis is done by the following equation, > DEAB =3D DEint + DEprep --> eqn. 1 >=20 > where DEAB is the dissociation energy or the binding energy. > DEint is the energy difference between the transition state and its = frozen fragments in the transition state.=20 > DEprep is the energy required to promote the fragments from their most = stable electronic ground state to the electronic ground state which they = possess in the transition state. >=20 > DEprep is obtained from the following procedures (1 or 2), >=20 > 1) Do single point energy calculation on each frozen fragments. > Then subtract the ground state energy of each fragment from the single = point energy of frozen fragment. Add each preparation energies to get = total DEprep. >=20 >=20 > DEprep =3D (E[frozen-F1]-E[optimized-F1]) + (E[frozen-F2]- = E[optimized-F2]) +.... > i.e DEprep =3D DEprep1 + DEprep2 + ... where DEprep1=3D = E[frozen-F1]-E[optimized-F1] in the above equation >=20 > 2) calculate DEAB and then subtract DEint. (see eqn. 1) >=20 > DEAB=3DE(optimized complex) -(E[optimized F1]-E[optimized F2]- .....) >=20 > where DEint =3D DEele + DEPauli + DEorb (which is directly obtained = > from EDA analysis). >=20 >=20 > Two procedures should give same DEprep. >=20 > On Fri, Apr 8, 2011 at 2:09 PM, may abdelghani may01dz:+:yahoo.fr = wrote: >=20 >=20 > Hello, > How to calculate the value of preparation energy "deltEpre" > from = energy decomposition analysis of ADF. >=20 > Thank you very much >=20 =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D= =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D dr. Marcel Swart ICREA Research Professor at Institut de Qu=EDmica Computacional Universitat de Girona Facultat de Ci=E8ncies Campus Montilivi 17071 Girona Catalunya (Spain) tel +34-972-418861 fax +34-972-418356 e-mail marcel.swart]![icrea.cat marcel.swart]![udg.edu web http://www.marcelswart.eu =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D= =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D --Apple-Mail-2--311976908 Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset=iso-8859-1 J. Am. Chem. Soc. 2004, 126, = 16718-16719
http://dx.doi.org/10.1021/ja0= 45276b

For systems containing = transition-metals, it also contains other terms
(valence = excitation, ligand-ligand):

M. = Swart
"Accurate spin-state energies for iron complexes"
J. Chem. = Theory Comput. 2008, 4, 2057-2066
http://dx.doi.org/10.1021/ct8= 00277a

And for other fragments, you may = need to include pairing as well:

F. M. = Bickelhaupt, E. J. Baerends 
The Case for Steric Repulsion = Causing the Staggered Conformation of Ethane 
Angew. = Chem. 2003, 115, 4315-4320
http://www3.interscience.wiley.com/cgi-bin/abstract/105557159/ABSTRA= CT

All that is explained in detail = in:

F. M. Bickelhaupt, E. J. = Baerends
Kohn-Sham Density Functional Theory: Predicting and = Understanding Chemistry
In: Rev. Comput. Chem.; K. B. Lipkowitz = and D. B. Boyd, Eds.; Wiley-VCH: New York, 2000, Vol. 15, pp. = 1-86

and in the above mentioned = papers.

For any specific ADF questions = (technical ones), it is better to have a look
at ADF forums = and ask the question there:
http://www.scm.com/forums/

Marcel

On Apr 8, 2011, at = 12:55 PM, Ajitha. John aji.john07|a|gmail.com wrote:

Dear abdelghani,

EDA analysis is done by the following equation,
DEAB =3D DEint + = DEprep  
          = -->   eqn. 1

where DEAB  is the dissociation energy or the binding = energy.
DEint is the energy difference between the transition state = and its frozen fragments in the transition state.
DEprep is the energy required to promote the fragments from = their most stable electronic ground state to the electronic ground state which = they possess in the transition state.

DEprep is obtained from the following procedures (1 or = 2),

1) Do single point energy calculation on each frozen fragments.
Then subtract the ground state energy of each fragment from the single = point energy of frozen fragment. Add each preparation energies to get total = DEprep.


DEprep =3D (E[frozen-F1]-E[optimized-F1]) + = (E[frozen-F2]- E[optimized-F2]) +....
i.e DEprep =3D DEprep1 +  DEprep2 +  ...    where = DEprep1=3D E[frozen-F1]-E[optimized-F1] in the above equation

 2) calculate DEAB and then subtract DEint. = (see eqn. 1)

DEAB=3DE(optimized complex) -(E[optimized = F1]-E[optimized F2]- .....)

where DEint =3D DEele + DEPauli +  = DEorb  (which is directly obtained from EDA analysis).


Two procedures should give same DEprep.

On Fri, Apr 8, 2011 at 2:09 PM, may abdelghani = may01dz:+:yahoo.fr <owner-chemistry . = ccl.net> wrote:


Hello,

How to calculate the value = of preparation energy "deltEpre" > from energy decomposition analysis of = ADF.

Thank you very = much

=

17071 = Girona
Catalunya = (Spain)

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=3D=3D=3D=3D=3D=3D=3D= =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D= =3D=3D=3D

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